Quadratics
Optimal Value
The highest or lowest value that the graph reaches
In order to find the Optimal Value of a standard form equation, you must first find the Axis of Symmetry by following the formula -b . Last, you need to plug that value into the formula and then be
2(a) ax²+bx+c
For Example
To find the Optimal Value of the standard y=3x²+8x+10, you must:
Step 1: Make the B value negative (y=3x²+8x+10)
8 turns into -8
Step 2: Divide the negative b value and divide by 2(a) (y=3x²+8x+10)
-8
2(3)
Step 3: Solve
-8 -8
2(3) 6
The axis of symmetry is x= -1.33
Step 4: Now that you have the axis of symmetry, plug it into the original equation
y=3x²+8x+10
y=3(-1.33)²+8(-1.33)+10
y=5.3067-10.64+10
y=4.6667
Therfore, the Optimal Value is y=4.6667
Question
What is the Optimal Value of (y=2x²+10x+13)?
Solution
To find the Optimal Value of the standard y=2x²+10x+13, you must:
Step 1: Make the B value negative (y=2x²+10x+13)
10 turns into -10
Step 2: Divide the negative b value and divide by 2(a) (y=2x²+10x+13)
-10
2(2)
Step 3: Solve
-10 -10
2(2) 4
The axis of symmetry is x= -2.5
Step 4: Now that you have the axis of symmetry, plug it into the original equation
y=2x²+10x+13
y=2(-2.5)²+10(-2.5)+13
y=512.5-25+13
y=0.5
Therfore, the Optimal Value is y=0.5

