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Optimal Value

 

The highest or lowest value that the graph reaches 

 

 

In order to find the Optimal Value of a standard form equation, you must first find the Axis of Symmetry by following the formula -b   . Last, you need to plug that value into the formula and then be 
          2(a)      ax²+bx+c                                                                                                                    

                                                                                                                                        

For Example

 

To find the Optimal Value of the standard y=3x²+8x+10, you must:

 

Step 1: Make the B value negative (y=3x²+8x+10)

 

          turns into -8

 

Step 2: Divide the negative b value and divide by 2(a) (y=3x²+8x+10)

 

          -8

          2(3)

 

Step 3: Solve 

 

          -8                     -8                                  

          2(3)                 6                

 

 

The axis of symmetry is x= -1.33

 

Step 4: Now that you have the axis of symmetry, plug it into the original equation

 

          y=3x²+8x+10

               

          y=3(-1.33)²+8(-1.33)+10

 

         y=5.3067-10.64+10

         

          y=4.6667

 

 

Therfore, the Optimal Value is  y=4.6667

 

Question

 

What is the Optimal Value of (y=2x²+10x+13)?

 

 

 

 

 

 

Solution

 

 

 

To find the Optimal Value of the standard y=2x²+10x+13, you must:

 

Step 1: Make the B value negative (y=2x²+10x+13)

 

          10 turns into -10

 

Step 2: Divide the negative b value and divide by 2(a) (y=2x²+10x+13)

 

        -10

          2(2)

 

Step 3: Solve 

 

          -10                     -10                                  

            2(2)                  4                

 

 

The axis of symmetry is x= -2.5

 

Step 4: Now that you have the axis of symmetry, plug it into the original equation

 

          y=2x²+10x+13

               

          y=2(-2.5)²+10(-2.5)+13

 

         y=512.5-25+13

         

          y=0.5

 

Therfore, the Optimal Value is  y=0.5

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